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4x^2-31x-1=x-65
We move all terms to the left:
4x^2-31x-1-(x-65)=0
We get rid of parentheses
4x^2-31x-x+65-1=0
We add all the numbers together, and all the variables
4x^2-32x+64=0
a = 4; b = -32; c = +64;
Δ = b2-4ac
Δ = -322-4·4·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{32}{8}=4$
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